## nuclear fusion

this is homework problem i'm having some trouble with... i haven't had chemistry yet so i'm not sure how i could convert atoms into kg, and the textbook i have doesn't do any examples of problems like this one... i don't even know where to begin.

Deuterium (A=2, Z=1) is an attractive fuel for fusion reactions because it is abundant in the waters of the oceans. In the oceans, about 0.015% of the hydrogen atoms in the water (H2O) are deuterium atoms.

(a) How many deuterium atoms are there in 4 kilogram of water?

(b) If each deuterium nucleus produces about 7.4 MeV in a fusion reaction, how many kilograms of ocean water would be needed to supply the energy needs of the United States for one year, estimated to be 9.3 1019 J? (answer should be in kg)
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 Quote by mayo2kett this is homework problem i'm having some trouble with... i haven't had chemistry yet so i'm not sure how i could convert atoms into kg, and the textbook i have doesn't do any examples of problems like this one... i don't even know where to begin. Deuterium (A=2, Z=1) is an attractive fuel for fusion reactions because it is abundant in the waters of the oceans. In the oceans, about 0.015% of the hydrogen atoms in the water (H2O) are deuterium atoms. (a) How many deuterium atoms are there in 4 kilogram of water?
How many hydrogen atoms are there in a kilogram of water? You should be able to get that by using the molecular weight (in kg/molecule) of water: the atomic weight of oxygen plus two times the atomic weight of hydrogen. Be sure to use kg/molecule! Multiply by 2 to get the number of hydrogen atoms in one kg of water (there are 2 hydogen atoms per water molecule of course). Multiply by 4 to get the number of hydrogen atoms in 4 kg of water. Finally, multiply by 0.015%= 0.00015 to get the number of deuterium atoms in 4 kg of water.,

 (b) If each deuterium nucleus produces about 7.4 MeV in a fusion reaction, how many kilograms of ocean water would be needed to supply the energy needs of the United States for one year, estimated to be 9.3 1019 J? (answer should be in kg)
Divide your previous answer by 4 to get the number of deuterium atoms in one kg of water and multiply by 7.4 MeV to get the energy, in MeV, in one kg of water. Now you will have to convert 9.2x1019 J to MeV to get the energy required in MeV. Finally, of course, divide the energy in MeV by the energy per kg of water to get your answer.
 i tried the first part but i'm not sure if this is what you meant... molecular weight of water = 18 g/mol = .018 kg/mol then: 2(.018kg/mol) = .036 hydrogen atoms in 1 kg of water 4kg(.036) = .144 hydrogen atoms in 4 kg of water .00015(.144) = 2.16e-15 number of deutrerium atoms in 4kg of water don't i need to use the avagadros number someplace?

## nuclear fusion

Yes, one needs to use Avogadro's number.

1 gram-mole = 6.022E23 atoms or molecules.

1 kg-mole = 6.022E26 atoms or molecules.

http://hyperphysics.phy-astr.gsu.edu...idegas.html#c4

 A mole (abbreviated mol) of a pure substance is a mass of the material in grams that is numerically equal to the molecular mass in atomic mass units (amu). A mole of any material will contain Avogadro's number of molecules. For example, carbon has an atomic mass of exactly 12.0 atomic mass units -- a mole of carbon is therefore 12 grams.