Emissivity e varies with zenith angle according to e = E*cos(theta)

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The discussion centers on the relationship between emissivity and zenith angle, specifically the equation e = E*cos(theta), where E represents the emissivity normal to the surface. It is established that since emissivity varies with angle, the flux density also varies, indicating that the surface radiates anisotropically. Callisto further clarifies that while the cosine law applies to intensity of incoming solar radiation, integrating intensity over an infinite plane surface results in isotropic radiation.

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Callisto
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If the emissivity e varies with zenith angle according to e = E*cos(theta) where E is the emissivity normal to the surface. Would this surface be an isotropic source of radiation?

Well, since e varies with angle then the flux density must vary accordingly so the surface would radiate anistropically.

Anybody disagree?
Callisto
 
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This cosine law is like the one for intensity of incoming solar radiation, and that's a cylinder, so I agree, anisotropic.
 
"Anisotropic" for a point on a surface; integrate intensity at any point above an infinite plane surface, and it's isotropic.
 

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