|Aug19-05, 11:15 PM||#1|
If the emissivity e varies with zenith angle according to e = E*cos(theta) where E is the emissivity normal to the surface. Would this surface be an isotropic source of radiation?
Well, since e varies with angle then the flux density must vary accordingly so the surface would radiate anistropically.
|Aug20-05, 11:55 AM||#2|
This cosine law is like the one for intensity of incoming solar radiation, and that's a cylinder, so I agree, anisotropic.
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