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Emissivity |
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| Aug19-05, 11:15 PM | #1 |
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Emissivity
If the emissivity e varies with zenith angle according to e = E*cos(theta) where E is the emissivity normal to the surface. Would this surface be an isotropic source of radiation?
Well, since e varies with angle then the flux density must vary accordingly so the surface would radiate anistropically. Anybody disagree? Callisto |
| Aug20-05, 11:55 AM | #2 |
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This cosine law is like the one for intensity of incoming solar radiation, and that's a cylinder, so I agree, anisotropic.
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| Aug20-05, 12:20 PM | #3 |
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"Anisotropic" for a point on a surface; integrate intensity at any point above an infinite plane surface, and it's isotropic.
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