Please help : Homework problem almost there ? Equilibrium

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SUMMARY

The discussion focuses on calculating equilibrium concentrations for the reaction between water and Cl2O to form HOCl, with a given equilibrium constant (Kc) of 0.090. Two scenarios are analyzed: mixing 1.00g of water with 4.78g of Cl2O in a 1.0L flask, and placing 1.0 mol of pure HOCl in a 2.0L flask. The equilibrium expression is correctly set up as Kc = [HOCl]² / ([H2O][Cl2O]), but participants emphasize the importance of using concentrations in the calculations. The reaction is identified as an acid-base reaction, suggesting a need for clarity in the stoichiometry and concentrations involved.

PREREQUISITES
  • Understanding of chemical equilibrium concepts
  • Familiarity with the equilibrium constant (Kc) and its application
  • Basic knowledge of stoichiometry in chemical reactions
  • Ability to calculate concentrations from mass and volume
NEXT STEPS
  • Learn how to derive equilibrium concentrations from initial concentrations and Kc values
  • Study the principles of acid-base reactions and their equilibrium expressions
  • Explore the use of ICE tables (Initial, Change, Equilibrium) in equilibrium calculations
  • Investigate the impact of changing conditions on equilibrium (Le Chatelier's Principle)
USEFUL FOR

Chemistry students, educators, and anyone involved in chemical equilibrium calculations, particularly in the context of acid-base reactions.

marioland
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linky

Kc = .090

a). Calculate the concn. of all species at equilibrium if 1.00g of water and 4.78g of ClO are mixed in a 1.0L flask.

b). Calculate the concn. of all species at equilibrium if 1.0 mol of pure HOCl is placed in a 2.0L flask. Hint: consider what is now the reactant.





H2O + Cl2O --> 2HOCl

I| 18mol 88 mol 0
C| -x -x +x
E| 18-x 88-x x

Kc= .090 = [HOCl]2 / [H2O].[Cl2O] = x2/(18-x)(88-x)


Solve for x and find all species.Is this the correct way ? Am I confusing you... *hmmm*
 
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You're getting there, but you could use a little hint --- the equilibrium constant is written for CONCENTRATIONS --- you've got the stoichiometry in the exponents correctly --- what are the "concentrations?"
 
You said that the reaction involved clo- and water which would be an acid base reaction.

Check to see if you wrote down the correct equation.

Acid base reaction would make more sense.
 

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