Ratzinger
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infinitely differentiable doesn't care if all the higher derivatives are zeroes (like for polynomials), it only has to be defined...correct?
Infinitely differentiable functions, also known as smooth functions, are defined as functions that possess derivatives of all orders. A key example discussed is the function f(x) defined as 0 at x = 0 and e^{-1/x^2} for x ≠ 0, which is infinitely differentiable despite all higher derivatives at x = 0 being zero. This characteristic highlights that infinitely differentiable functions do not require non-zero derivatives to maintain their classification. Understanding these functions is crucial for advanced mathematical analysis and applications in various fields.
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