Figuring Out Patent Blue Solution Concentration

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SUMMARY

The discussion focuses on calculating the amount of Patent Blue V (E 131) needed to create a mother solution with a concentration of 1.00 x 10^-3 mol/L in a 1.00 L volume. The molar mass of Patent Blue V is established as 1160 g/mol. To determine the required mass of Patent Blue V, the formula used is: mass = moles x molar mass, where moles are calculated by multiplying concentration by volume. Thus, 1.00 L of the mother solution requires 1.16 grams of Patent Blue V.

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Hello :blushing:

I need help trying to figure this out:

Patent blue V is a food coloring designed under the code E 131. Using a scales of blue tints, we hope to determine the molar concentration of patent blue in a solution used to color candy in a candy shop. We make a range of tints starting from the volume V = 1,00 l of the "mother solution" So, of the concentration C in patent blue equal to 1,00*10^-3 mol.L-1.

Here's the information given before the question:

Molar mass od patent blue : M = 1160 g.mol-1
Patent blue is a solid that does not react to water.

Question:

How much patent blue needs to be dissolved in order to make the mother solution?

I don't know which formula to use in order to solve this. Any suggestions?

P.S. Sorry if this is extremely hard to understand, the exercise was originally given to me in french. :shy:
 
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How many moles of patent blue are in 1 L of your desired mother solution w/ your desired concentration?


Concentration (in molarity) x volume= moles
 
thank you... simply put :shy:
 

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