Did Police Make the Right Call in Speeding Arrest Based on Skid Mark Length?

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Homework Help Overview

The discussion revolves around the determination of whether a driver was exceeding a speed limit of 30 miles per hour based on the length of skid marks measuring 19.2 feet. The police's assumption regarding the maximum deceleration related to the acceleration of a freely falling body is central to the inquiry.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between skid mark length and initial speed using kinematic equations. There are questions about the correctness of the calculations and the implications of unit conversions.

Discussion Status

Some participants are questioning the accuracy of the initial calculations and the assumptions made regarding deceleration. There is a divergence in interpretations of the results, with differing conclusions about whether the driver was speeding.

Contextual Notes

Participants note the importance of unit consistency in calculations and the potential implications of using different acceleration values. There is also mention of converting units from feet per second to miles per hour, which may affect the interpretation of the results.

courtrigrad
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The question is whether a driver is exceeding a 30 miles/hr speed limit before he makes an emergency stop. The length of the skid marks on the road is 19.2 feet. The police assumed that the maximum deacceleration of the car would not exceed the acceleration of a freely falling body and arrested the driver for speeding. Was this correct to do?

So the acceleration of a freely falling body is [itex]a = -32 \frac{ft}{sec^{2}}[/itex]. So [itex]v_{x}^{2} = v_{x}_{0}^{2} + 2a_{x}(x-x_{0}})[/itex]. Since [itex]v_{x} = 0[/itex], [itex]0 = v_{x}_{0}^{2} - 64(19.2)[/itex]. So [itex]v_{x}_{0}^{2} = 1228.8[/itex] and [itex]v_{x}_{0} = 35[/itex]. So he was speeding. Is this correct?

Thanks
 
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Be careful with your units! You used 32 ft/s^2 for the acceleration and 19.2 feet for the distance. What are the units of v? :)
 
[itex]v_{x}_{0} = 35 \frac{ft}{sec}[/itex]. Is this correct?

Thanks
 
So, was the driver speeding?
 
no he wasnt. he was only traveling 23.86 miles per hour. I converted ft/sec to miles/hour.
 

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