Need Help With College Algebra Factoring

Click For Summary
SUMMARY

The discussion focuses on factoring the polynomial Y^6 + 124Y^3 - 125. The recommended approach is to substitute X = Y^3, transforming the expression into X^2 + 124X - 125. This substitution simplifies the factoring process, allowing users to consider the various methods to factor 125. After factoring, it is essential to revert X back to Y^3 in the final answer.

PREREQUISITES
  • Understanding polynomial expressions and their degrees
  • Familiarity with substitution methods in algebra
  • Knowledge of factoring techniques for quadratic equations
  • Basic skills in manipulating algebraic expressions
NEXT STEPS
  • Study polynomial substitution techniques in algebra
  • Learn about factoring quadratic equations, specifically using the quadratic formula
  • Explore methods for factoring higher-degree polynomials
  • Practice solving polynomial equations with real-world applications
USEFUL FOR

Students studying college algebra, educators teaching factoring techniques, and anyone looking to improve their algebraic manipulation skills.

AshyLarry
Messages
5
Reaction score
0
Y^6+124Y^3-125

the ^ means to the power of
asks to factor

help :biggrin:
 
Last edited:
Physics news on Phys.org
Substitute X = Y³
 
AKG's suggestion, replace Y3 with X is the best start. Once you do that you will have X2+ 124X- 125 (because Y6= (Y3)2), To factor that, think about the different possible ways to factor 125.
(And don't forget to put Y3 back into the answer in place of X.)
 

Similar threads

  • · Replies 43 ·
2
Replies
43
Views
15K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
5K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 22 ·
Replies
22
Views
8K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 13 ·
Replies
13
Views
12K
  • · Replies 1 ·
Replies
1
Views
3K