Calculating Drop Locations: The Physics of Water Dripping from a Shower Nozzle

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Homework Help Overview

The problem involves calculating the positions of water drops falling from a shower nozzle, specifically focusing on the timing and distance of the drops as they fall 81 inches to the floor. The subject area includes kinematics and motion under gravity.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need for a position function and the implications of initial velocity in the context of the problem. There is a focus on determining the timing of each drop's fall and the reasoning behind the intervals at which the drops are released.

Discussion Status

The discussion is ongoing, with participants exploring the relationship between the timing of the drops and the distance fallen. Some have provided insights into the calculation of time for the first drop to hit the floor and how that relates to the timing of subsequent drops.

Contextual Notes

Participants note that the drops fall at regular intervals, and there is a specific emphasis on understanding why the interval is one-third of the time it takes for the first drop to reach the floor.

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Water drips from the nozzle of a shower onto the stall floor 81 in. below. The drops fall at regular intervals of time, the first drop striking the floor at the instant the fourth drop begins to fall. Find the location of the individual drops when a drop strikes the floor.

So we are given a distance the drop falls 81 inches . When it says to find the location of the individual drops, I need a position function. Should I use [itex]y = v_{y}_{0}t + \frac{1}{2}a_{y}t^{2}[/itex]?

Thanks
 
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Right, but there's no initial velocity. And first you need to find the time each drop starts falling.
 
Or, more correctly, the initial velocity is 0! Calculate the time it takes the first drop to hit the floor. According to the problem, that is exactly the time the fourth drop starts to fall. So, since the drops fall "at regular intervals of time", that "regular intervals of time" is 1/3 the time the first drop takes to hit the floor (do you see why it is 1/3 and not 1/4?). Now you know when each successive drop starts!
 
yes that's what i was thinking. its 1/3 and not 1/4, because the first drop hits the ground only when the fourth drop starts to fall, not when it hits the ground.
 

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