What is the area bounded by Y=X^1/2, the x-axis, and 2X+3Y=6?

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Homework Help Overview

The problem involves finding the area bounded by the curve Y=X^1/2, the x-axis, and the line 2X+3Y=6. This falls within the subject area of calculus, specifically dealing with integration and area under curves.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss finding the intersection points of the curves to determine limits of integration. There is also a suggestion to consider integrating with respect to y, indicating different approaches to the problem.

Discussion Status

The discussion is ongoing, with participants exploring various methods to approach the problem. Some guidance has been offered regarding finding intersection points and considering different integration perspectives, but no consensus has been reached yet.

Contextual Notes

There is a mention of the problem being a homework question, which may impose certain constraints on how it should be approached or discussed.

tuly
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hello everybody...please could you help me find the solution for this problem??

find the area bounded by the curve Y=X^1/2, the x-axis, and the line 2X+3Y=6.
 
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Find the intersection point of the two lines to get an idea of your limits of integration. After that you'll want to integrate the difference of the two expressions to find the area between them.
 
1. whozum's suggestion

2. Are you sure you copied this correctly? This looks like a homework problem (and so, really should be in the homework section!) and my experience is that, in homework problems, the point of intersection works out more simply than this does.

3. You may find it easier to think of the "height" of the figure as running in the x-direction and integrating with respect to y.
 
thank u

thanks for your help...
 

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