Electric Transients: Solving RC Circuits Problems

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Discussion Overview

The discussion focuses on solving problems related to RC circuits, specifically involving the charging and discharging of capacitors. Participants explore the application of the time constant in calculating the voltage across a capacitor at given times during these processes.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant presents two problems involving an RC circuit with specified time constants and initial voltages, seeking assistance in determining the time at which the voltage reaches certain values.
  • Another participant requests the formula for voltage or charge as a function of time, suggesting that it would help guide the original poster in solving the problems.
  • A later reply provides the correct formula for voltage as a function of time, emphasizing the use of logarithms to solve for time.
  • Subsequent posts include calculations by the original poster, applying the formula to both problems and arriving at specific time values for each scenario.

Areas of Agreement / Disagreement

Participants generally agree on the approach to solving the problems using the exponential decay formula, but there is no explicit consensus on the correctness of the calculations presented.

Contextual Notes

The discussion does not address potential assumptions or limitations in the problems, such as the ideal behavior of the components in the circuit or the conditions under which the formulas apply.

Who May Find This Useful

Students or individuals studying electrical engineering or physics, particularly those focusing on circuit analysis and the behavior of capacitors in RC circuits.

cunhasb
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I would really appreciate if anyone could help me figure out these problems...

An RC circuit has a time constant of 40 microseconds. If the capacitor is first charged to a voltage of 80 volts and the RC circuit is then closed upon itself, after what time will the capacitor voltage be equal to 5 volts?... and

An RC circuit has a time constant of 0.0001 second. If the capacitor C is charged to 100 volts and, with the battery removed, the capacitor is then allowed to discharge through the resistor, at what time after being connected to the resistor will the voltage be 20 volts? (Assume that, in discharging, the voltage V at any time is equal to V=V(0) e^(-1/RC), where V(0) is the voltage to which C was charged.)

Thank you so much guys...
 
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Can you write out the formula for voltage or charge as a function of time, given the time constant?

Then we can point you in the right direction if necessary.
 
cunhasb said:
I would really appreciate if anyone could help me figure out these problems...

An RC circuit has a time constant of 40 microseconds. If the capacitor is first charged to a voltage of 80 volts and the RC circuit is then closed upon itself, after what time will the capacitor voltage be equal to 5 volts?... and

An RC circuit has a time constant of 0.0001 second. If the capacitor C is charged to 100 volts and, with the battery removed, the capacitor is then allowed to discharge through the resistor, at what time after being connected to the resistor will the voltage be 20 volts? (Assume that, in discharging, the voltage V at any time is equal to V=V(0) e^(-1/RC), where V(0) is the voltage to which C was charged.)

Thank you so much guys...
Your formula is independent ot the time. The correct formula would be:
[tex]V(t) = V(0)e^{-\frac{t}{RC}}[/tex]
Where [tex]RC[/tex] is the time constant. If you replace V(0) with the initial value of the voltage and V(t) with the final value, you can use logarithms to solve for the time [tex]t[/tex].
 
Thank you so much guys...

well... I think I got it... correct me if I'm wrong...

1) Rc= 40 micro V(0) = 80 T=? V = 5V

V=v(0) e^(-t/RC)
5=80*e^(-t/RC)
5/80=e^(-t/RC)
RC*ln0.0625=-t
t=110.903 microseconds...

2) Rc= 0.0001 V(0) = 100 T=? V = 20V

V=v(0) e^(-t/RC)
20=100*e^(-t/RC)
20/100=e^(-t/RC)
RC*ln0.2=-t
t=160.94 microseconds...
 
That's it.
 

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