
#1
Sep605, 10:15 PM

P: 322

A 58.0 kg iceskater moving at 6.25 m/s glides to a stop. Assuming the ice is at 0°C and that 53.5 percent of the heat generated by friction is absorbed by the ice, how much ice melts?
Should I first calculate the work? I know I need to use Delta U= QW...but what is Delta U in this case? 



#2
Sep605, 10:23 PM

HW Helper
P: 508

53.5% of the kinetic energy is converted to heat energy which is delta U.




#3
Sep605, 11:54 PM

P: 322

How do I find Q given to the ice?




#4
Sep705, 06:16 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,898

latent heat of fusion of ice
First, calculate the kinetic energy of the skater initially. Since the skater completly loses that energy, it must have gone into heat caused by the friction with the ice.
Find 53.3% of that and apply that to the "heat of melting" of ice. 


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