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question about light and blackholes |
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| Nov20-03, 10:15 PM | #18 |
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question about light and blackholes
Gravitons escape the warp of a black hole with no problem and with no loss to gravitational energy.
Does that mean gravity travels faster than light (escaping the event horizon of a black hole?) |
| Nov20-03, 10:17 PM | #19 |
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| Nov22-03, 07:29 PM | #20 |
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How do we observe and verify something going faster than light? |
| Nov22-03, 10:49 PM | #21 |
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| Nov23-03, 02:53 PM | #22 |
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To put it another way, when there is an eclipse and the earth is in shadow, there is no "shadow wave" emanating from the moon, the shadow is simply an effect of the moon blocking the sun, there are no "shadowtons" or shadow waves. So what I'm asking is does gravity emanate from a source as a wave, in the way that light radiates from a source, or are we simply seeing the tell tale effects of gravity within a defined sphere of an inert source? |
| Nov23-03, 03:06 PM | #23 |
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Gravitational waves can emanate from a source as a wave, analogous to how light (electromagnetic waves) radiates from a source. But electromagnetic waves are not responsible for, say, the electrostatic attraction (or repulsion) between two charges, nor are gravitational waves intrinsically responsible for the attraction of two masses. Nothing has to "emanate" from a mass or charge, in the sense of some effect propagating at some speed through space, in order for one body to influence another. (But if you change the source, then the effects of that change will propagate out in terms of changes in the field at successively more distant points.) |
| Nov23-03, 04:04 PM | #24 |
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| Dec6-03, 01:10 AM | #25 |
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This is so heavy spicoli! Nothing escapes the black hole period. NOTHING NOTHING. Not even your thought waves:)
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| Dec8-03, 05:47 AM | #26 |
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[QUOTE]Originally posted by magus
[B]i was just wandering..... at the point where gravity is strong enough to be greater than the kinetic energy of which light possesses, do photons of light actually radiate some distance from the collapsed star then slow to rest and fall back to the surface, as a cannonball being shot straight up in Earth's atmosphere would, or at this point are the particles simply not capable of being emitted. or is their some other explanation of which i have not accounted for. thx, the point of which you are speaking, is called the event horizon. light particals are not able to withstand the graivty of the sigularity. Thus they are sucked in. They don't go out and then get sucked into a black hole, they just go into the black hole. Now when they are sucked in, they give of a nasty gamma burst that is detectible. They give this off because of the energy that is involved with clashing into a singulary which is like smashing into Earths atmosphere. And that is what can detect it, with other obsevations of course. |
| Dec8-03, 06:00 AM | #27 |
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the event horizon is the edge of a black hole. the gavity there is greater than you can imagine. if light is going into the black hole, you are not going to see it. When light clashes with the event horizon of a black hole, it give off gamma rays. Thats it, that is the only way to see it. If you could optically see a black hole, it wouldn't be a black hole
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| Dec8-03, 10:04 AM | #28 |
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