Register to reply 
Please help, Express kinetic energy in terms of m and p? 
Share this thread: 
#1
Sep1405, 12:59 PM

P: 24

Hi, I think my brain froze and i'm not seeing it
the problem is the momentum is defined as p=mv=m(dx/dt) express the kinetic energy in terms of m and p ~ Now I know kinetic = T= (1/2)mv^2 and that P=mv I figured that it must be t= (1/2)p^2 till i realized that I'm missing in terms of m. I just got stumped 


#2
Sep1405, 01:24 PM

P: 34

T= (1/2)p^2
You know p=mv, so p^2 gives (mv)^2 T=/= (1/2)(mv)^2 where =/= represents 'is not equal to' I suspect that you will kick yourself when it dawns on you. 


#3
Sep1405, 01:25 PM

P: 48

p=mv > v=p/m
T=1/2*m*v^2 T=1/2*m(p/m)^2 > T=1/2((p^2)/m) 


Register to reply 
Related Discussions  
Express tan(2x) in terms of sin(x) alone.  Calculus & Beyond Homework  3  
What is the meaning of chemical energy, in terms of first principles?  Chemistry  14  
Mechanical Energy vs Potential Energy & Kinetic Energy  Introductory Physics Homework  3  
Kinetic Terms  High Energy, Nuclear, Particle Physics  4  
Express sin4x in terms of sinx?  General Math  3 