Please help, Express kinetic energy in terms of m and p?


by belleamie
Tags: energy, express, kinetic, terms
belleamie
belleamie is offline
#1
Sep14-05, 12:59 PM
P: 24
Hi, I think my brain froze and i'm not seeing it
the problem is

the momentum is defined as
p=mv=m(dx/dt)
express the kinetic energy in terms of m and p

~ Now I know kinetic = T= (1/2)mv^2
and that P=mv
I figured that it must be t= (1/2)p^2
till i realized that I'm missing in terms of m. I just got stumped
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Theoretician
Theoretician is offline
#2
Sep14-05, 01:24 PM
P: 34
T= (1/2)p^2

You know p=mv, so p^2 gives (mv)^2

T=/= (1/2)(mv)^2

where =/= represents 'is not equal to'

I suspect that you will kick yourself when it dawns on you.
Ene Dene
Ene Dene is offline
#3
Sep14-05, 01:25 PM
P: 48
p=mv -> v=p/m

T=1/2*m*v^2

T=1/2*m(p/m)^2 -> T=1/2((p^2)/m)


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