The total mechanical energy (E) of a 2 kg mass oscillating on a spring with a spring constant of 50 N/m and a maximum velocity of 5 m/s is calculated to be 25 Joules. The formula used is E = (1/2)mv^2 + (1/2)kx^2. At the equilibrium position, the displacement (x) is zero, simplifying the equation to E = (1/2)(2)(5)^2, resulting in 25 Joules of energy. This calculation demonstrates the relationship between mass, velocity, and spring constant in oscillatory motion.
PREREQUISITESStudents of physics, mechanical engineers, and anyone interested in understanding the dynamics of oscillatory systems and energy calculations.