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Solve the system. |
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| Sep14-05, 11:26 PM | #1 |
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Solve the system.
y=x^2
y=x-1/4 I really need help with this question. i don't know how to do these types of questions with fractions. i can't think, i need to sleep
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| Sep15-05, 03:57 PM | #2 |
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Edit: I jumped a step. Both equations are equal to y, so [tex]x^2=x-\frac{1}{4}[/tex]
Get everything onto the same side of the equation. You have a quadratic equation. Factoring fractions really isn't that much different than integers. You figure out the combinations that will equal 1/4 when multiplied together. For example: [tex]\frac{1}{4}* 1 = \frac{1}{4}[/tex] [tex]\frac{1}{2}*\frac{1}{2} = \frac{1}{4}[/tex] and so on. Add the combinations together and hopefully one of them will equal your middle coefficient (1 in this case). |
| Sep15-05, 04:23 PM | #3 |
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Recognitions:
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| Sep15-05, 05:04 PM | #4 |
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Solve the system.As BobG suggests, since y=x^2 replace y in (4y=4x-1) by x^2: 4(x^2)=4x-1. Then, as EnumaElish suggests, use the quadratic formula [after writing it in standard form]. An alternate method is to plot the two curves (one is a parabola and one is a line) then locate the intersection points. |
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