How can I write this sequence in terms of factorials?

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    Factorial Sequences
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Discussion Overview

The discussion revolves around expressing the mathematical expression n((n^2)-1) in terms of factorials. Participants explore different approaches to rewrite the expression, focusing on the factorial representation rather than simple factorization.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant, Martin, requests assistance in rewriting the expression n((n^2)-1) in terms of factorials, suggesting that the answer is (n+1)!/(n-2)!, but expresses uncertainty about how to arrive at this conclusion.
  • Another participant points out that n(n^2-1) can be factored into n(n-1)(n+1), which may be a step towards the factorial representation.
  • Martin clarifies that the goal is to find a factorial expression, emphasizing the importance of understanding the factorial notation and its implications.
  • Martin later suggests expanding the numerator and denominator of the proposed factorial ratio and canceling common factors as a method to derive the solution.
  • Martin expresses gratitude for the hints provided, indicating some level of progress in understanding the problem.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the method to derive the factorial expression, and multiple approaches are discussed without resolution.

Contextual Notes

The discussion includes assumptions about the manipulation of factorials and the specific steps required to transition from the polynomial expression to a factorial representation, which remain unresolved.

martinrandau
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Can anybody help me solving this?

Write in terms of factorials

n((n^2)-1)

The correct answer is
(n+1)!/(n-2)!

but I don't know how to get there, and since it's week- end I have no chance to ask anyone teachers, etc.
//Martin
 
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n(n2-1) = n(n-1)(n+1)
 
Originally posted by martinrandau
Can anybody help me solving this?

Write in terms of factorials

n((n^2)-1)

The correct answer is
(n+1)!/(n-2)!


Please notice the expression marks (!). The task is not to factorise it by "normal" means, but to find an expression as a sequence.
ex. 7! = 1 x 2 x 3 x 4 x 5 x 6 x 7 = 5040
n!= 1 x 2 x 3 x...x n

It's called the factorial r (!).
Thank you for your help anyway!
 
Originally posted by martinrandau
The correct answer is
(n+1)!/(n-2)!

I'll give you a hint.

Expand the numerator and denominator of the above ratio and cancel the factors common to both. For instance, the numerator is:

(n+1)!=(n+1)(n)(n-1)(n-2)...

Get the idea?
 
Yes!:smile:
Thank you!

//Martin
 

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