What Is the Probability of Correctly Guessing the Colors of Cards?

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Homework Help Overview

The discussion revolves around a probability problem involving four cards, two red and two black, placed face down. The original poster seeks assistance in determining the probability of correctly guessing the colors of the cards when guessing randomly.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants explore the probabilities of getting 0, 2, or 4 guesses correct. There are discussions about the basic probabilities for individual guesses and the application of binomial probability concepts. Some participants question the setup and the assumptions made regarding the guessing process.

Discussion Status

There are various interpretations of the problem being discussed, with some participants providing insights into the probability calculations. However, there is no explicit consensus on the approach or the final probabilities, and the conversation remains open-ended.

Contextual Notes

Some participants have pointed out that the original poster may have posted in the wrong forum, suggesting that probability questions should be consolidated in a specific thread for clarity.

Alexsandro
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Hello, I tried to model and answer this question, but I didn't get success. Could someone help me ?

You are told that of the four cards face down on the table, two are red and two are black. If you guess all four at random, what is the probability that you get 0, 2, 4 right ?
 
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Please PAY ATTENTION to where you are posting. You want one of the homework subforum, and NOT the Academic and Career Guidance.

Zz.
 
There are two possible colors for a card and they are equally likely. Whatever you guess, what is the probability your guess will be correct for a specific card?

What is the probability that all 4 guesses are correct? What is the probability that all 4 guesses are wrong?

The probability that exactly two of your guesses are correct is harder. If you know about "binomial probability", then this is exactly the same as aking for the probability that, if you flip a coin 4 times, it will come up heads exactly twice. Imagine writing "C" for "correct" if you guess a coin correctly, "N" for "not correct" if you guess incorrectly. The difference between this problem and the first two is that if you were guess correctly all 4 times you would write CCCC and there is only one way of doing that, if you were to guess correctly 0 times, you would write NNNN and there is only one way of doing that, but if you guess correctly exactly twice you might have written CCNN, or NNCC, or CNCN, etc. How many different ways are there of writing two C's and two N's?
 
You have six possibilities as follow

R,R B,B
R,B,B,R
R,B,R,B
B,B,R,R
B,R,B,R
B,R,R,B

B IS BLACK , R IS RED

P( o right)= 1/6

P(2 right)= 2*2/6=2/3

P(4 right)=1/6
 

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