Why does the n 'fall out' of the square root in the Pythagorean theorem formula?

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The discussion centers on the Pythagorean theorem and the manipulation of the formula involving the variable 'n'. Specifically, it addresses the transition from the expression v = u + n² to the subsequent steps where 'n' appears to be removed from the square root. The participants clarify that 'n' is treated as a constant in this context, allowing for simplification in the equation. This understanding is crucial for correctly applying the theorem in various mathematical scenarios.

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I postet the formula below (attachment). I don't know how we can get from the first step to the second. I mean why does that n fall "out" of the square root?
 

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Step 1a, let v=u+n2, then lower limit of v is n2
Step 1b, let u=v

I presume w is independent of u.
 

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