How Do You Calculate Initial Speed in Projectile Motion Problems?

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SUMMARY

The discussion focuses on calculating initial speed in projectile motion problems, specifically addressing two scenarios: a ball thrown horizontally from a height of 22 m and a projectile fired at an angle of 30° from a height of 41 m. In both cases, the final speed is related to the initial speed, with the first scenario resulting in a final speed three times the initial speed and the second scenario yielding a final speed of 1.4 times the initial speed. The participants emphasize the importance of separating vertical and horizontal components of motion, particularly noting that only the vertical component experiences acceleration due to gravity.

PREREQUISITES
  • Understanding of projectile motion principles
  • Familiarity with kinematic equations, specifically V^2=Vo^2+2ah
  • Knowledge of vertical and horizontal motion components
  • Basic algebra for solving equations
NEXT STEPS
  • Study the derivation and application of kinematic equations in projectile motion
  • Learn how to separate vertical and horizontal components in projectile problems
  • Explore the effects of different launch angles on projectile trajectories
  • Practice solving various projectile motion problems with different initial conditions
USEFUL FOR

Students and educators in physics, particularly those focusing on mechanics and projectile motion, as well as anyone seeking to improve their problem-solving skills in kinematics.

heeling23
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1. A ball is thrown horizontally from a height of 22 m and hits the ground with a speed that is three times its initial speed. What was the initial speed?

2. A projectile is fired with initial speed v at an angle 30° above the horizontal from a height of 41 m above the ground. The projectile strikes the ground with a speed of 1.4v. Find v.

These are essentially the same problems right? Except for the fact that #2 has a vertical initial velocity. I tried using V^2=Vo^2+2ah but I got the answer wrong. Then I tried finding the time for the first one using y=1/2at^2 and then using v=vo+at and I got the wrong answer again.

Any help is appreciated!
Thanks,
heeling23
 
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heeling23 said:
I tried using V^2=Vo^2+2ah but I got the answer wrong. Then I tried finding the time for the first one using y=1/2at^2 and then using v=vo+at and I got the wrong answer again.
Either approach, done correctly, would work. Post the details of what you did for more help. (Hint: Only the vertical component of motion is accelerated.)
 

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