Integration/calc work? what did i do wrong

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The discussion centers on the integration of the function Int[1/(x^2+4)^2] using the substitution x = 2 tan(q). The user successfully transforms the integral into 1/(4 tan^2(q) + 4)^2 but struggles with further simplification and substitution techniques. They consider using u-substitution with tan(q) = u, where du = sec^2(q) dq, to facilitate the integration process. The final expression derived is 1/(16 sec^4(q)), indicating a potential path forward for solving the integral.

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Int[1/(x^2+4)^2]
let x= 2 tan(q)
i get 1/(4 tan^2(q) + 4)^2
I get 1/ (16 tan ^4(q) + 32 (1-sec^2(q) + 16)
and now i think about doing a u-substituition with tan x=u, du =sec^2 (x) can i do that!?! :mad:
 
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do you just don't like my topics i want help in?
 
[tex]\frac{1}{(4\tan(q)+4)^2} = \frac{1}{16\sec^4q}[/tex]
 

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