Calculate CaCO3 Mass: Stoichiometry Help for Decomposition Reaction

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Discussion Overview

The discussion revolves around a stoichiometry problem involving the decomposition of calcium carbonate (CaCO3) into calcium oxide (CaO) and carbon dioxide (CO2). Participants are calculating the mass of CaCO3 based on the amount of CO2 released and discussing how to determine the percentage by mass of CaCO3 in a mixture.

Discussion Character

  • Homework-related
  • Mathematical reasoning

Main Points Raised

  • One participant calculates the moles of CO2 produced and subsequently the mass of CaCO3, arriving at 3.5097 g of CaCO3 based on the decomposition reaction.
  • There is a question regarding the correct method to calculate the percentage by mass of CaCO3 in the original sample, with one participant suggesting dividing the mass of CaCO3 by the total mass of the sample.
  • Another participant confirms the calculation method for the percentage by mass, indicating that the initial suggestion seems correct.

Areas of Agreement / Disagreement

Participants generally agree on the calculation of the mass of CaCO3 and the method for calculating the percentage by mass, although there is some uncertainty expressed regarding the approach to the percentage calculation.

Contextual Notes

There is an assumption that the only source of CO2 in the original sample is from the decomposition of CaCO3. The discussion does not clarify whether any other components in the mixture could affect the calculations.

Who May Find This Useful

Students or individuals seeking assistance with stoichiometry problems, particularly those involving decomposition reactions and percentage calculations in chemistry.

Soaring Crane
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a. A sample of CaCO3 decomposes when heated to form calcium oxide and carbon dioxide. 1.5432 g of CO2 are released in the reaction. Find g of CaCO3 in the original sample.
CaCO3 --> CO2 + CaO

1.5432 g CO2*(1 mol of CO2/44.01 g) = 0.035065 mol of CO2*(1 mol CaCO3/1 mol CO2) = 0.035065 mol CaCO3

0.035065 mol CaCO3*(100.09 g/ 1mol CaCO3) = 3.5097 g CaCO3??


b. The original sample was a mixture from which only CaCO3 released carbon dioxide. Calculate the percentage by mass of CaCO3 if original's sample mass was 5.768 g.


Do I divide 3.5097 g CaCO3/5.768 g * 100 or must I subtract the grams of CO2 from the original sample's mass?

Thanks.
 
Last edited:
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Any volunteers?

Thanks again.
 
Soaring Crane said:
a. A sample of CaCO3 decomposes when heated to form calcium oxide and carbon dioxide. 1.5432 g of CO2 are released in the reaction. Find g of CaCO3 in the original sample.
CaCO3 --> CO2 + CaO

1.5432 g CO2*(1 mol of CO2/44.01 g) = 0.035065 mol of CO2*(1 mol CaCO3/1 mol CO2) = 0.035065 mol CaCO3

0.035065 mol CaCO3*(100.09 g/ 1mol CaCO3) = 3.5097 g CaCO3??
That's correct.


b. The original sample was a mixture from which only CaCO3 released carbon dioxide. Calculate the percentage by mass of CaCO3 if original's sample mass was 5.768 g.


Do I divide 3.5097 g CaCO3/5.768 g * 100 or must I subtract the grams of CO2 from the original sample's mass?

Thanks.
This looks a little silly, but your first idea seems right.
 
all seemed right: (3.5097/5.768)*100 should do it.
 

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