How Much Current Is Needed for a Solenoid to Generate a Specific Magnetic Field?

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SUMMARY

The discussion focuses on calculating the current required for a solenoid to generate a magnetic field of 0.385 T. The solenoid in question is 50.0 cm long with a diameter of 1.25 cm and contains 975 turns of wire. The relevant formula used is B = μ₀ nI, where 'n' represents the number of turns per unit length, calculated as n = N/L. The diameter is not directly used in the calculation but is important for ensuring the solenoid is considered long enough for the formula to apply.

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jena
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Hi,

My Question:

A 50.0-cm long solenoid 1.25cm in diameter is to produce a field of 0.385 T at its center. How much current should the solenoid carry if it has 975 turns of the wire?

I know that I have to use this equation:

B = \mu _0 nI


where I'm stuck at is with the length do I used the how long it is with the diameter or do i just ignore the diameter :confused:

please help

Thank You :smile:
 
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1
The formula you have written is for a long solenoid such that L >>R, to insure this, I think the dimeter is given, otherwise you have to use general formula for the field.
2
In this formula 'n' is the number of turns per unit length n = N/L.
 

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