How Is Time Calculated for a Ball Thrown Upwards?

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SUMMARY

The time taken for a ball thrown upwards with an initial speed v from a height h to strike the ground can be calculated using kinematic equations. Specifically, the equation \( t = \frac{v + \sqrt{v^2 + 2gh}}{g} \) is derived from the principles of motion under gravity, where g represents the acceleration due to gravity. This formula accounts for both the initial velocity and the height from which the ball is thrown. Understanding this relationship is crucial for solving related physics problems accurately.

PREREQUISITES
  • Kinematic equations of motion
  • Understanding of gravitational acceleration (g)
  • Basic algebra for solving equations
  • Concept of projectile motion
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Students studying physics, educators teaching kinematics, and anyone interested in understanding the principles of motion related to projectiles.

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A ball is thrown straight upward with a speed v from a point h metres above the ground. Express the time taken for the ball to strike the ground in terms of v,g and h.
(this question would be worth 4 marks on an assignment, so please answer according to the allocated marks) Thank you:smile:
 
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I'll first say that you should show some work because you're about to get pounced on for asking for answers.

Here's my tip... what kinematic equation(s) relate(s) the variables you mentioned?
 

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