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Old Oct3-05, 10:30 PM                  #1
erik-the-red

erik-the-red is Offline:
Posts: 89
Calculating a force constant using kinetic and potential energy?

You are designing a delivery ramp for crates containing exercise equipment. The crates weighing LaTeX Code: 1500 N will move at a speed of LaTeX Code: 2.00 m/s at the top of a ramp that slopes downward at an angle LaTeX Code: 24.0^\\circ. The ramp exerts a kinetic friction force of LaTeX Code: 540 N on each crate, and the maximum static friction force also has this value. Each crate will compress a spring at the bottom of the ramp and will come to rest after traveling a total distance of LaTeX Code: 7.90 m along the ramp. Once stopped, a crate must not rebound back up the ramp.

Question:

Calculate the force constant of the spring that will be needed in order to meet the design criteria.

My answer is 27.4 N/m, but I am not quite sure that it is correct.

I know LaTeX Code: K_1=(1/2)(1500/9.80)(2.00^2)=306 J

LaTeX Code: K_2 is zero. LaTeX Code: U_1 is also zero. LaTeX Code: W_f is LaTeX Code: -4270 J . I define LaTeX Code: x_2=7.90m .

So, I should use the equation LaTeX Code: K_1+U_1+W_f=mgy_2+(1/2)(k)(x_2)^2 .

LaTeX Code: y_2=x_2*sin(24.0^\\circ)=3.21 . But, it is -3.21 because LaTeX Code: y_2 is below LaTeX Code: y_1=0 .

Using the equation I believe I should use, I got the answer to be LaTeX Code: k=27.4 m/s.
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