Register to reply

Partial Derivative

by dimensionless
Tags: derivative, partial
Share this thread:
Oct5-05, 04:44 PM
P: 464
I'm trying to figure out this equation.

{\Psi} = Ae^{-a(bx-ct)^2}

I've expanded this to

{\Psi} = Ae^{-ab^2x^2-abxct-ac^2t^2}

When I try to find the derivative I get this

\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }

\pd{\Psi}{t}{}\right)_x = (-2ac^2t-abxc)Ae^{-ab^2x^2-abxct-ac^2t^2}

I should get this instead

\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } }

\pd{\Psi}{t}{}\right)_x = (-2abcx-2ac^2t)Ae^{-ab^2x^2-abxct-ac^2t^2}

Can anyone tell me where my error is and how I can fix it?
Phys.Org News Partner Science news on
New type of solar concentrator desn't block the view
Researchers demonstrate ultra low-field nuclear magnetic resonance using Earth's magnetic field
Asian inventions dominate energy storage systems
Oct5-05, 05:25 PM
Sci Advisor
krab's Avatar
P: 905
Try again in expanding

Register to reply

Related Discussions
Converting partial derivative w.r.t. T to partial derivative w.r.t. 1/T Calculus & Beyond Homework 2
Replacing total derivative with partial derivative in Griffiths' book Advanced Physics Homework 3
Partial Derivative Calculus & Beyond Homework 0
Partial derivative General Math 14
Total derivative -> partial derivative Differential Equations 6