## Partial Derivative

I'm trying to figure out this equation.

$${\Psi} = Ae^{-a(bx-ct)^2}$$

I've expanded this to

$${\Psi} = Ae^{-ab^2x^2-abxct-ac^2t^2}$$

When I try to find the derivative I get this

$$\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } } \pd{\Psi}{t}{}\right)_x = (-2ac^2t-abxc)Ae^{-ab^2x^2-abxct-ac^2t^2}$$

$$\left(\newcommand {\pd}[3]{ \frac{ \partial^{#3}{#1} }{ \partial {#2}^{#3} } } \pd{\Psi}{t}{}\right)_x = (-2abcx-2ac^2t)Ae^{-ab^2x^2-abxct-ac^2t^2}$$
 Recognitions: Science Advisor Try again in expanding $$(bx-ct)^2$$