Problem


by Werg22
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Werg22
Werg22 is offline
#1
Oct5-05, 09:05 PM
P: 1,520
http://img338.imageshack.us/img338/9397/circle9sr.jpg

The question goes;

B is the center of the arc AC and BD is perpendicular to AE, proove that
AD = DE + EC

I've been on it for hours now and I can't find anything...
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amcavoy
amcavoy is offline
#2
Oct5-05, 09:18 PM
P: 669
Quote Quote by Werg22
http://img338.imageshack.us/img338/9397/circle9sr.jpg

The question goes;

B is the center of the arc AC and BD is perpendicular to AE, proove that
AD = DE + EC

I've been on it for hours now and I can't find anything...
The way I am thinking of is fairly long, but here it is:

Use the law of cosines. Note that angle BAC=BCA.

[EC]2=[AE]2+[AC]2+2cosθ

where θ is the angle EAC. Try working it out and let me know if you get stuck.

Alex
amcavoy
amcavoy is offline
#3
Oct7-05, 11:11 AM
P: 669
Sorry, that should be ...-2[AE][AC]cosθ in the above equation.

Alex


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