|Oct5-05, 09:05 PM||#1|
The question goes;
B is the center of the arc AC and BD is perpendicular to AE, proove that
AD = DE + EC
I've been on it for hours now and I can't find anything...
|Oct5-05, 09:18 PM||#2|
Use the law of cosines. Note that angle BAC=BCA.
where θ is the angle EAC. Try working it out and let me know if you get stuck.
|Oct7-05, 11:11 AM||#3|
Sorry, that should be ...-2[AE][AC]cosθ in the above equation.
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