Problemby Werg22 Tags: None 

#1
Oct505, 09:05 PM

P: 1,520

http://img338.imageshack.us/img338/9397/circle9sr.jpg
The question goes; B is the center of the arc AC and BD is perpendicular to AE, proove that AD = DE + EC I've been on it for hours now and I can't find anything... 



#2
Oct505, 09:18 PM

P: 669

Use the law of cosines. Note that angle BAC=BCA. [EC]^{2}=[AE]^{2}+[AC]^{2}+2cosθ where θ is the angle EAC. Try working it out and let me know if you get stuck. Alex 



#3
Oct705, 11:11 AM

P: 669

Sorry, that should be ...2[AE][AC]cosθ in the above equation.
Alex 


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