#1
Oct805, 01:04 PM

P: n/a

1.) S and P waves, simultaneously radiated from the hypocenter of an earthquake, are received at a seismographic station 17.3 s apart. Assume the waves have traveled over the same path at speeds of 4.50 km/s and 7.80 km/s. Find the distance from the seismograph to the hypocenter of the quake.
The text doesn't thoroughly explain how to do these types of questions. So, I can't even explain what I did, since i have no beginning point. 2.) Two waves in one string are described by y1 = 3cos(4x  1.6t) y2 = 4sin(5x  2t) Find superposition. The formula I have for the addition of two wave functions requires both functions to be sin and also for the amplitudes to be equal. So, I made y1 = 3sin(4x  1.6  pi/2). However, how do i deal with the uncommon bases? 3.) Two pulses travel on string are described as functions: y1 = 5 / ( (3x  4t)^2 + 2) y2 = 5 / ( (3x + 4t  6t^2) + 2) When will the two waves cancel everywhere? At what point to the two pulses always cancel? I noticed that that y2 is reflected on the xaxis, and has a phase constant. Also, it is moving to the left, while y1 moves to the right. Firstly, what are the conditions under which the waves will cancel everywhere? For two waves to cancel everywhere, would they not have to have equal phase constants (which these do not? Also, what are the conditions for the waves to cancel? I propose that the functions be added, and the values be found which would cause y to equal = 0. However, there is both x and t variables! Thank you for any help you can provide on this urgen issue. 



#2
Oct805, 01:57 PM

HW Helper
P: 661

d1 = v1 x t1, v1 = 4.5km/s (1) d1 = v2 x t2, v2 = 7.8km/s (2) You also know that (t2t1) = 17.3 (3) Three unknown variables (d1, t1, t2), three equations as listed. Solved. y1 + y2 = 0, for all x. Solve for t. I can see the math getting pretty ugly however. The second part is the opposite of the first. At what point/points do the two pulses always cancel. The condition here is then. y1 + y2 = 0, for all t. Solve for x. Again, may get ugly mathematically ^^;; 



#3
Oct805, 01:58 PM

P: 8

x=vt. the two waves have the same distance, but different times and velocities. set the equation to solve for the known difference in time and you should get it from there. I hope that wasn't too much info. 


#4
Oct1505, 06:29 PM

P: n/a

Waves: Standing Waves, Superposition, etc.I ended up with x = 48t  36 / 48t  36 = 1 However, how do I solve for t? 



#5
Feb1906, 03:48 AM

P: 62

well that means for any value of t other than t=36/48 sec the above equation will be satisfied



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