Proof of Parallelogram for Regular Quadrilateral

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Homework Help Overview

The discussion revolves around proving that the figure formed by joining the midpoints of the sides of any regular quadrilateral is a parallelogram. The subject area includes geometry and discrete mathematics.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore both vector and non-vector proofs. There are questions regarding the definition of a "regular" quadrilateral, with some suggesting that it may only refer to squares, while others propose considering rhombuses or any quadrilateral. Hints about using mid-segments of triangles are also mentioned.

Discussion Status

The discussion is active, with participants questioning the assumptions about what constitutes a regular quadrilateral and exploring different approaches to the proof. There is no explicit consensus on the definitions or methods, but hints and suggestions have been provided to guide the exploration.

Contextual Notes

Some participants express difficulty in starting the proof and seek assistance, indicating a potential lack of clarity in the problem setup or definitions.

SS2006
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Prove that for any regular quadrilateral, the figure formed by joining the midpoint of the four sides will always be a parallelogram

vector proof
AND
non vector proof

this is geometry and discrete mathematics btw.
 
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Aren't YOU the one who was given that problem? What have you done on it?
 
oh i can't get started
i hate proofs, i was hoping somenoe can get me started :)
 
What exactly do you mean by a "regular" quadrilateral?? Normal a "regular" polygon has all sides and all angles congruent. The only "regular" quadrilaterals are squares and that's much too easy. It's more interesting if you are only assuming sides are of the same length (a rhombus).
 
HallsofIvy said:
What exactly do you mean by a "regular" quadrilateral?? Normal a "regular" polygon has all sides and all angles congruent. The only "regular" quadrilaterals are squares and that's much too easy. It's more interesting if you are only assuming sides are of the same length (a rhombus).

it is even more interesting if it was any quadrilateral.

here is a hint, use mid-segements of a triangle.
 

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