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hot metal + water = Tf??? |
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| Oct16-05, 05:49 AM | #1 |
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hot metal + water = Tf???
Yet again I find i am stumped by having no clue as to what I did in this incredibly easy problem.
1 = water 2 = copper m1c1 delta T1 = -m2c2 delta T2 This simplifies to... m1= (-m2c2 delta T2)/(c1 delta T1) which is... (-(110*.2*(25.6-82.4)))/((4.18*(25.6-22.3)) = 95.8533g Computer says i'm wrong and it slapped me I then did the lazy way and calculated the energy required to lower the copper's temperature. With that, I manually figured out how much water there was and got the exact same answer. Where am I going wrong here? |
| Oct16-05, 05:59 AM | #2 |
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Significant digits? I don't know...
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| Oct16-05, 06:03 AM | #3 |
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Did you do your numerical calculation right? Isn't the answer 90.59 g?
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| Oct16-05, 03:07 PM | #4 |
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hot metal + water = Tf???
I tried 3 and 4 sig. figures with +/- 1 each direction and nothings coming out correctly. God i wanna pound the writers of this textbook.
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