Prove the quotient theorem using the limit definition?

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SUMMARY

The discussion focuses on proving the quotient theorem using the limit definition, specifically addressing the limit of the function f(x) as x approaches a, equating to A, and the limit of g(x) as x approaches a, equating to B. The limit expression provided is lim_{h→0} (f(x+h)/g(x+h) - f(x)/g(x))/h, which simplifies to lim_{h→0} (f(x+h)g(x) - f(x)g(x+h))/(hg(x+h)g(x)). The participants emphasize the importance of confirming that lim_{h→0} g(x+h) = g(x) to complete the proof.

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  • Understanding of limit definitions in calculus
  • Familiarity with the quotient theorem in calculus
  • Basic knowledge of algebraic manipulation of limits
  • Experience with mathematical notation and expressions
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franz32
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Hello guys!

I'm new here! Well, it feels like this forum is cool and interesting!

Can anyone help me here? =)

How do you prove the quotient theorem using the limit definition?
(Given a limit of f of x as x approaches a is A and a limit of g of x as x approaces a is B).
 
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[tex] \begin{equation*}\begin{split}<br /> \lim_{h\rightarrow 0} \frac {\frac {f(x+h)} {g(x+h)} - \frac {f(x)} {g(x)}} {h} <br /> &= \lim_{h\rightarrow 0} \frac {f(x+h)g(x) - f(x)g(x+h)} {hg(x+h)g(x)} \\<br /> &= \lim_{h\rightarrow 0} \frac {f(x+h)g(x) - f(x)g(x) + f(x)g(x) - f(x)g(x+h)} {hg(x+h)g(x)}<br /> \end{split}\end{equation*}[/tex]
You can take it from here. Be careful. How do you know
[tex]\lim_{h\rightarrow0} g(x+h)=g(x)[/tex]?
 
Last edited:
Thank you... =)

Hello. =)

Well, I think I can take it from here. If I have doubts,

I would probably want to clarify it.

Anyway, thank you very much!
 

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