Continuous functions with multiple variables

Click For Summary
SUMMARY

The discussion focuses on determining the values of two multivariable functions to ensure continuity at the point (0,0). The first function, f(x,y)=sqrt(x^2+y^2)/[abs(x) + abs(y)^(1/3)], approaches an indeterminate form of 0/0, but analysis shows that f(0,0) can be defined as 0 due to the numerator decreasing faster than the denominator. The second function, f(x,y)=(x^2 + y^2)*ln(x^2 + 2y^2, results in the indeterminate form of -0*infinity, complicating the continuity assessment. The discussion highlights the challenges of applying single-variable calculus techniques, such as L'Hôpital's rule, to multivariable functions.

PREREQUISITES
  • Understanding of multivariable calculus concepts
  • Familiarity with limits and continuity in functions of multiple variables
  • Knowledge of L'Hôpital's rule and its application
  • Basic logarithmic properties and their implications in calculus
NEXT STEPS
  • Study the application of L'Hôpital's rule in multivariable calculus
  • Research methods for evaluating limits of multivariable functions
  • Explore the concept of continuity in higher dimensions
  • Learn about the behavior of logarithmic functions near zero
USEFUL FOR

Students and professionals in mathematics, particularly those studying multivariable calculus, as well as educators seeking to clarify concepts of continuity and limits in functions of multiple variables.

cappygal
Messages
9
Reaction score
0
I need to find a value for f at (0,0) to make this function continuous:

f(x,y)=sqrt(x^2+y^2)/[abs(x) + abs(y)^(1/3)]

With other functions in this problem I simply took the limit .. but taking the limit gives 0/0. In single-variable calculus I would apply l'hopital's rule to this, but I'm not sure what to do with multiple variables.

I also need to do the same for:

f(x,y)=(x^2 + y^2)*ln(x^2 + 2y^2)

For this one, you get 0*0, again an indeterminant form. In single variable I would manipulate it until I got 0/0 and then apply l'hopital .. but I'm lost in multivariable.
 
Physics news on Phys.org
In f(x,y)=sqrt(x^2+y^2)/[abs(x) + abs(y)^(1/3)] the numerator goes to 0 faster than the denominator (e.g. along x=y); so my guess is f(0,0) = 0.

0*0 is not indet., it is 0. But ln(0) = -infty so you have -0*infty, which is indet. I don't have an answer for that one (yet).
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 40 ·
2
Replies
40
Views
6K
  • · Replies 34 ·
2
Replies
34
Views
4K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
Replies
8
Views
2K