Chain rule confusion partial derivatives

Click For Summary
SUMMARY

The discussion focuses on the application of the chain rule in calculus to compute partial derivatives, specifically dz/dt and dw/dt. The variables are defined as follows: w = xy + yz², x = e^t, y = e^t*sin(t), and z = e^t*cos(t). The confusion arises when attempting to derive dz/dt, as z is not a function of x or y. The correct approach involves recognizing that dz/dt can be computed directly since z is solely a function of t, while dw/dt requires the application of the chain rule with respect to x, y, and z.

PREREQUISITES
  • Understanding of the chain rule in calculus
  • Familiarity with partial derivatives
  • Knowledge of functions of multiple variables
  • Basic differentiation techniques
NEXT STEPS
  • Study the application of the chain rule in multivariable calculus
  • Learn how to compute partial derivatives using specific examples
  • Explore functions of several variables and their derivatives
  • Practice problems involving derivatives of composite functions
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable functions and derivatives, as well as educators seeking to clarify the chain rule and partial derivatives.

mr_coffee
Messages
1,613
Reaction score
1
Hello everyone...
I'm very confused...
i'm suppose to find
dz/dt and dw/dt
but for some of the questions there is no w variable! so what do u put for dw/dt?! Also i have the following:
w = xy + yz^2; x = e^t; y = e^t*sint; z = e^t*cost;
so I'm trying to find dz/dt and dw/dt;
dz/dt = dz/dx * dx/dt + dz/dy * dy/dt + dz/dw * dw/dt;
but when i try dz/dx * dx/dt i need to first take the partial derivative of z with respect to x, but as you can see, z has no x variable! so what do i do about that? THanks!
 
Physics news on Phys.org
how do you get dz/dt = dz/dx * dx/dt +dz/dy * dy/dt + dz/dw * dw/dt

dz/dt[e^t * cos t] = cos t * e^t - sint * e^t

there is no dx

as far as dw/dt

it would be

dw/dx * dx/dt + dw/dy * dy/dt + dw/dz + dz/dt
 
mr_coffee:

You need to keep track of what is a function of what.

You have:

[tex]w = xy + yz^2; x = e^t; y = e^t \sin t; z = e^t \cos t[/tex]

So, you have:

[tex]w = w(x,y,z); x = x(t); y = y(t); z=z(t)[/tex]

If you want to find dz/dt, it's just a simple derivative, since z is only a function of t, and not of x or y or w.

To find dw/dt you need the chain rule:

[tex]\frac{dw}{dt} = \frac{\partial w}{\partial x} \frac{dx}{dt} + \frac{\partial w}{\partial y} \frac{dy}{dt} + \frac{\partial w}{\partial z} \frac{dz}{dt}[/tex]
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
12
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 28 ·
Replies
28
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 23 ·
Replies
23
Views
3K
Replies
2
Views
2K
Replies
5
Views
4K