## why is the limit 2025? a simple plug and chug limit! gone wrong!

Hello everyone i have the following prlbem:
lim (x,y)->(5,-2) (x^5+4x^3y-5xy^2);

So i let y be fixed at 0 and let x equal 5, and i got 5^5 which is 3125, if i let 0, and y be -2 i get 0. Doesn't this mean the limit doesn't exist? but it says its 2025, ?
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 Just plug in 5 for each x value and -2 for each y value, you get 2025. You were doin something completely different.
 ohhh i did that before and i messed up on multipcation thank u

Recognitions:
Homework Help
$$\lim _{x \to 7} x^2$$