Voltage Across Resistor in Series Circuit: Impossible?

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SUMMARY

The discussion centers on the behavior of voltage in a series circuit when one resistor is open. With a total voltage of 24V across the series resistors, if one resistor is open, the voltage across that resistor equals the total applied voltage, which is 24V. The voltage drop across the remaining resistors is zero due to the absence of current flow (I = 0) in the circuit. This confirms that in a series circuit, an open resistor results in no voltage drop across other resistors.

PREREQUISITES
  • Understanding of Ohm's Law (V = I * R)
  • Knowledge of series circuit configurations
  • Familiarity with voltage measurement techniques
  • Basic electrical theory regarding current flow
NEXT STEPS
  • Study the implications of an open circuit in series configurations
  • Learn about voltage measurement tools such as multimeters
  • Explore troubleshooting techniques for identifying open resistors
  • Research the effects of series and parallel circuits on voltage distribution
USEFUL FOR

Electrical engineering students, hobbyists working with circuits, and anyone involved in troubleshooting series circuits will benefit from this discussion.

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for the question:
the toal voltage across a string of seires resistors is 24V. If one of the resitors is open, how much voltage is there across it? How much is there across each of the good resitors?

my problem:
isn't it impossible to find which part is open in a series circuit without using something to measure it?
 
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The voltage drop across a resistor = I * R, where I = current and R = resistance.

If the I = 0, which is the case when a resistor is open, then the voltage drop is what ever the applied voltage is across the resistor, and there is no voltage drop across the other resistors.
 
right~ opps... i think i might be going overload lately~
thanks!
 

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