schattenjaeger
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say if you get a result for a0 but 0 for an and bn(using my book's notation where the Fourier series is a0+an*cos(nx)+bn*sin(nx)
The discussion confirms that a Fourier series can indeed represent a constant function. Specifically, when the coefficients an and bn are both zero, the Fourier series simplifies to just the constant term a0. This outcome occurs when the original function being analyzed is constant, as demonstrated in the context of Fourier series notation a0 + an*cos(nx) + bn*sin(nx).
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