Solving the Water-Lifting Puzzle: An Analysis of Efficiency and Output

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SUMMARY

The discussion centers on calculating the amount of water a pump can lift in one minute when lifting water 5.0 meters high using a pump with a power output of 1.0 kW, where only 65% of the power is utilized for lifting. The effective lifting work is calculated as 39 kJ per minute. To determine the volume of water lifted, participants discuss the relationship between energy, mass, and height, ultimately leading to the formula mgh to solve for mass.

PREREQUISITES
  • Understanding of basic physics concepts, specifically gravitational potential energy.
  • Familiarity with power calculations and energy conversion (1 kW = 1000 J/s).
  • Knowledge of the relationship between mass, volume, and density of water.
  • Ability to manipulate algebraic equations to solve for unknowns.
NEXT STEPS
  • Research the principles of gravitational potential energy and its applications.
  • Learn about energy efficiency in mechanical systems, focusing on pumps.
  • Explore the relationship between mass, volume, and density in fluid mechanics.
  • Investigate real-world applications of pump efficiency in agricultural settings.
USEFUL FOR

Farmers, agricultural engineers, and anyone involved in optimizing water lifting systems for irrigation purposes.

Izekid
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A farmer uses a pump to lift water from a river to a arable land who lies 5.0m higher than the river. The pump exhaust an electrical effect of 1.0kW but only 65% is used to do the lifting. ok A) I have resolved the lifting work is 0,65*60 = 39kJ

But B) is harder,,,, how much water is pumped up during a minute ...?

I have no idea how to solv this please help me
 
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In A) you've apparently solved how much work is used to lifting the water a minute.
During this minute, how much water is lifted?
Is the anwer in kg or m3? Doesn't really matter, you know their relation.

What is the energy required to lift a ball of mass m to height h?
 
You know that 65% of the pumps power (1 kW) is used to lift water.
This means that every second, 650 J of energy is used by the pump to list water, multiply by 60 to get energy per minute.
You know how much energy it will take to lift m kilograms of water h distance up against gravity g (mgh), since in this problem h and g are givens/constants, so just solve for m.
 

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