Small Oscillations: Spring Constant & Frequency

Click For Summary
SUMMARY

The discussion focuses on the relationship between small oscillations, spring constants, and frequency in mechanical systems. It establishes that the effective spring constant (k) for small oscillations is determined by the second derivative of the potential energy function. The frequency (ω) is defined as ω = sqrt(k/m). A specific example is provided using a pendulum with potential energy U(t) = mgL(1-cos(t)), leading to an effective spring constant of mgL and a frequency of ω = sqrt(gL). The confusion arises when comparing this to the accepted formula, which is clarified by substituting the moment of inertia (I = ml²) instead of mass (m).

PREREQUISITES
  • Understanding of potential energy functions in mechanics
  • Familiarity with the concept of small oscillations
  • Knowledge of derivatives and their application in physics
  • Basic grasp of pendulum dynamics and moment of inertia
NEXT STEPS
  • Study the derivation of the potential energy function for different oscillatory systems
  • Learn about the mathematical treatment of small angle approximations in pendulum motion
  • Explore the relationship between moment of inertia and angular frequency in rotational dynamics
  • Investigate the applications of harmonic motion in real-world systems
USEFUL FOR

Students of physics, mechanical engineers, and anyone interested in the principles of oscillatory motion and their mathematical foundations.

asdf60
Messages
81
Reaction score
0
For small oscillations, the oscillation behaves like a spring, because the potential energy function can be approximated by a parabola at the equilibrium point. Now, the effective spring constant in these situations is equal to the second derivative of the potential energy function, and so the frequency w = sqrt(k/m), where k is the second derivative of the potential energy function.

I'm confused by this. In particular, I don't understand when this actually works. For example, for a pendulum, the potential energy function is U(t) = mgL(1-cos(t)), where t is theta. In this case the effective spring constant is mgL, so w = sqrt(gL). Obviously this doesn't agree with the accepted formula (which is also for small angles only). So what's going on here?
 
Physics news on Phys.org
Hmm, it occurs to me now that if insead of m, i use the moment of inertia I = ml^2, i get the right formula. Is this a coincidence?
 
Yes, if you write it as a function of x, horizontal displacement, rather than theta, it comes out all right.
 

Similar threads

Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
2K
Replies
9
Views
3K
Replies
2
Views
1K
Replies
13
Views
2K
Replies
19
Views
2K
Replies
3
Views
1K
  • · Replies 11 ·
Replies
11
Views
2K