What is the equation of a line passing through (5,4) and (5,-6)?

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Homework Help Overview

The discussion revolves around finding the equations of lines given specific points and slopes, particularly focusing on cases with zero and undefined slopes. The original poster expresses confusion regarding the nature of these slopes and how to formulate the equations based on the provided points.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to understand the relationship between slope and the equations of lines, questioning how to derive equations from points with both zero and undefined slopes. They explore the implications of these slopes on the equations and express uncertainty about the differences between them.

Discussion Status

Participants are actively engaging with the problem, with some offering affirmations of correctness regarding the original poster's thoughts. There is an ongoing exploration of the concepts, with no clear consensus yet on the best approach to take.

Contextual Notes

The original poster mentions difficulty in recalling methods for determining the equations of lines, indicating a potential gap in foundational understanding. They also express uncertainty about the relevance of graphing in this context.

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Write an equation of a line with a slope of 0 and passing through the point (5,4).

Write an equation of a line with an undefined slope and passing through the point (-2,4).


I know how to do this type of thing but these two questions have stumped me.

If the slope of the first one is zero, it'll be a horizontal line. That means the equation will look something like this: y= some number right?

If so, what do I do with the (5, 4)? Do I just graph that point and see where it is as far as y goes? If that's what I'm to do...*Looks at a graph* y= 4? Now that I think about it, I didn't need the graph so that either means it's really easy or really wrong.:smile:

As for the second one, if the slope is undefined it would be vertical and would look like this: x= some number. Would it be the same way, again, assuming I did the first one right? x= -2?

EDIT: Write an equation of a line that passes through (9,-5) and (3,-5).

The slope is 0/-6, right? Does that make it undefined or 0? I can't tell the difference. What if the answer was -6/0? Which would that be?

As for writing the equation, it would be x or y, whichever it is according to whether it's undefined or zero...y/x = Aw, geez, I don't even know how to go about this one...

Write an equation of a line that passes through the points (2,3) and (2,-6).

slope = -9/0

I have two points...so, what I would do is...hm, would graphing them help me or not?
 
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Your answers are correct. So maths can be simple...
 
Thanks.:smile:

I suppose I was a bit late with my edit...:smile:

Write an equation of a line that passes through (9,-5) and (3,-5).

The slope is 0/-6, right? Does that make it undefined or 0? I can't tell the difference. What if the answer was -6/0? Which would that be?

As for writing the equation, it would be x or y, whichever it is according to whether it's undefined or zero...y/x = Aw, geez, I don't even know how to go about this one...*Pulls out her notes* I can't find anything referring to this type of problem...Method 1: If you are given the equation of the line, put the equation in slope intercept form. Nope, that's not it. Method 2: If you are given the graph of the equation, count the change in y and the change in x on the graph paper to determine the slope. Nope, not right either. Method 3: Nope, that only shows how to find the slope (I used method three for this one...) but it doesn't show what to do next...

Write an equation of a line that passes through the points (2,3) and (2,-6).

slope = -9/0

I have two points...so, what I would do is...hm, would graphing them help me or not?
 
Look at the points. What do you see?
 
I don't know...I don't know what I'm supposed to be seeing. I've looked at them already so if I wasn't seeing it before I'm not seeing it now.:shy: :smile:
 
Never mind, got it. ^_^
 

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