How to Calculate Enthalpy and Entropy Change for SiC Heating?

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Homework Help Overview

The discussion revolves around calculating the change in enthalpy and entropy for 1 mole of silicon carbide (SiC) when heated from 25 degrees Celsius to 1000 degrees Celsius, using a provided specific heat capacity equation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the relationship between heat capacity and entropy, referencing the integral form of entropy change. Questions arise regarding the assumptions of constant pressure and the absence of non-expansion work in the problem setup.

Discussion Status

The discussion is active, with participants questioning the assumptions necessary for applying the equations. Some guidance is provided regarding the interpretation of specific heat capacity and the typical conditions assumed in thermodynamic problems.

Contextual Notes

There is an ongoing examination of the assumptions related to constant pressure and the nature of work done by the system, with no explicit resolution reached on these points.

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how do you solve the following problem?

calculate the change in enthalpy and the change in entropy when 1 mole of SiC is heated from 25 degrees C to 1000 degrees C.
Cp=50.79+1.97*(10^-3)T-4.92*(10^6)(T^-2)+8.2*(10^8)(T^-3) J/(mole*K)
 
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The variation of Entropy with temperature for a system is given by
[tex]S(T_f) = S(T_i) + \int \frac{dq_{rev}}{T}[/tex]
When the system is under constant pressure and there is no non-expansion work,
[tex]dq_{rev} = C_p dT[/tex]
 
how do you know that the question is under constant pressure?
 
because they give u Cp, which is the specific heat at constant pressure
 
@@
how do you know that there's no non-expansion?
 
Non expansion work is work done by the system other than in expansion.
For example, electrical work. So unless it is specifically stated, there is usually no non-expansion work.
 
thank you very much!
 

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