Calculating the magnetic field of 3 piece wire

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SUMMARY

The magnetic field at point P, located at the center of a half-circle arc formed by a wire carrying a current of 5.78A, has been calculated correctly. The radius of the arc is 0.0789m. The formula used, B = μ0*i/(2*π*R), yields a magnetic field strength of 1.14X10^-4T when the values are substituted appropriately. This confirms the accuracy of both the calculations and the formula employed.

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GrassPuppet
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Okay I need some verification that I did this problem right. If not then please tell me where I went wrong.

Given a long wire going into the page with current also going in the same direction and then making a half-circle arc along the plane of the paper to the left, and finaly conituing to make a straight wire. Find the magnetic field at P which is at the center of the arc (center of circle if the arc were a full circle). I'm given the radius of the arc and the current.

i=5.78A
R=.0789m
I used phi=Pi
I attached the formula I used and a poor drawing of what the wire looks like.

segment.View attachment arc.doc

I got 1.14X10^-4T
 
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Yes, your solution is correct. Your formula is also correct - the magnetic field at P is given by B = μ0*i/(2*π*R). Plugging in the values you provided, you get B = 4π*10^-7 * 5.78/(2*π*.0789) = 1.14X10^-4T. Therefore, your answer is correct.
 

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