Finding Critical Numbers

cdhotfire

Well, I got this equation [latex]f(x)=\frac{2\sin{2x}}{x}[/latex] [latex] [-\pi,\pi][/latex]
So I took the 1st derivative, [latex]f'(x)=\frac{2(2x\cos{2x} - \sin{2x})}{x^2}[/latex]
Then I set that equal to 0, and got [latex]0=2x\cos{2x} - \sin{2x}[/latex]
But I do not see how to get the critical numbers, I also tried to do double angle, but that just resulted in more pain.
Any help, would be appreciated.

cdhotfire

Please.

Tide

Haven't I seen this somewhere before? :)

cdhotfire

ya, i know, i though no one visited the mathematics section, because i was only able to join it by using the search tool. Also, i put a note for someone to delete my post in the other section.

btw, i posted back on you reply.