How Do You Find the Maximum of C(T) = 2t/(t+3)^2?

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SUMMARY

The maximum of the function C(T) = 2t/(t+3)^2 can be found by calculating its derivative and setting it equal to zero. The derivative can be determined using the quotient rule: (f'(x)g(x) - f(x)g'(x))/(g(x)^2). Identifying critical points where the slope is zero will lead to the maximum value of the function.

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almohandes
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can someone please help me with this, I've been having trouble with it.

C(T)= 2t/(t+3)^2

find the maximum?

thanks
 
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Do you know how to find the derivative of the function? If so then check when the slope is equal to 0.
To find the derivative use the (f'(x)g(x) - f(x)g'(x))/(g(x)^2)
 
If you've "been having trouble with it", then you must have tried something! What have you tried? Exactly where are you having trouble?
 

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