- #1
chwala
Gold Member
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Find the value of x between 0 degrees and 360 degree satisfying the equation
10sin^2x+ 10sin x cos x - cos^2x = 2 this is how i have attempted.....
10 sin^x+ 10sin2x/2 - cos^x = 2
I used the property sin 2x = 2 sin x cos x and substituted sin x cos x with sin 2x/2 giving me....
11sin^2x + 5sin 2x -3 =0 on reaching here i got stuck...kindly advise
10sin^2x+ 10sin x cos x - cos^2x = 2 this is how i have attempted.....
10 sin^x+ 10sin2x/2 - cos^x = 2
I used the property sin 2x = 2 sin x cos x and substituted sin x cos x with sin 2x/2 giving me....
11sin^2x + 5sin 2x -3 =0 on reaching here i got stuck...kindly advise