Thanks!
Just another thing, the answer came to be 1900ppm in 0.250L. I had to dilute it so that I took 0.01L from that solution and made it up to 0.1L. To find the ppm of the diluted solution is it as simple as dividing the ppm by 25? Because I took 1/25 of the solution?
I'm not sure since...
Ah yeah I get what you mean. The question is asking to calculate the concentration of Fluoride in mg/L (PPM).
I'm guessing this would lean to where the steering wheels mass is much less than the cars mass? So I need to use 19 (MW of F-) in the PPM equation?
Since it's a 0.1M conc. of NaF...
Oh right! So the PPM of Fluoride still will be 4213.59?
So it's like saying out of 50 cars you'll still only have 50 steering wheels?
Do my calculations look ok?
Thanks!
Homework Statement
Calculate PPM of *Fluoride* in standard solution. NaF (dissolved in solution) = 1.0534g in 0.250L distilled water.
Homework Equations
PPM = Mol/L * g/mol * 1000
c=n/V
n=m/M
The Attempt at a Solution
C=n/V, n = m/M
n = 1.0534/41.99 = 0.02509
c = n/V =...