Charles Link's latest activity

It works for the case where there are no torques, but the expression for the torques gets much more complicated with any accelerations...

One comment to the above is by attaching the observation point to the rod, it is now in an accelerated frame. If you keep the...

It may be worth mentioning that as odd as angular momentum can be there is the case where we get the same results from all of the...

To add to post 64, it may be worth mentioning the center of percussion. If you have a door swing on a hinge or are swinging a baseball...

Indeed. This problem was educational for me in that it jarred me out my complacency of "having seen it all."

It might be worth taking an extra look at what we have observed in this problem from working it from a couple of different reference...

ok, thanks for checking it all out.

They solved for ## u ## using ## \cos{\theta}=1/3 ##. (Their result does agree with what we both got). I anticipate that's why there is...

This problem is from the Indian National Physics Olympiad – 2020. A "tentative" solution appears here on page 15.

Yes, the point of attachment moves, but my reference point doesn't. Let’s say there is a mark on the table at P. That is my reference...

I'll say it again: my reference point for the angular momentum calculation is fixed. It is the point in space where the attachment...

an update to my post 46 that I just included an "Edit": I recomputed ## u ##, and I now agree with @haruspex post 45 result for ##...

In post 31 @haruspex seems to offer a solution to what occurs after the impulse response. The discussion though focused mostly on the...

Yes, I foolishly thought that the CM velocity need not be added. That agreement vis-à-vis what the problem was asking is another point...

@kuruman Somewhat good, but you forgot to include ## v_{cm} ## to the velocity of the left end of the rod for the first part. Once you...