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Let me expand on this, because there's a seemingly obvious response that Coleman gives a little later in the lecture, using David...

Yeah, after my reply to Demystfier #48, I also became unsure. If his argument should be too weak to explain why we see a single...

Not for Coleman. For him, the relevant Hilbert space is that of the dots. For Coleman, there are states ##|none\rangle## and...

In the given setup, L is the measurement operator. So you don't observe indiviual atoms at all. You just observe L. And in the simple...

Note that Coleman's operator L operates on the state of the cloud chamber |C⟩, not on the initial or scattered particle. L looks at the...

Yes. And if Demystifier agrees that his Hilbert space should have been (at least) 4 dimensional instead of 2 dimensional, then his...

Let us first agree on Demystifier's example. He thinks it generalizes to more complicated scenarios. And what Coleman says on page 10 is...

Let us look at the 4-dimensional Hilbert space for Demystifier's simplified scenario. On L is defined on the "corresponding" basis via L...

I no longer believe that Coleman‘s operator can tell us that:

After some thinking, I think the Mott-Coleman argument is simply wrong, because the operator ##L## does not exist. To explain it in...

Your problem is that you model the state of the chamber as a two dimensional Hilbert space. But even with just one ionizable atom on...

The argument is at the bottom of slide 15a (page 9) together with Coleman's words on page 10: It is basically just a trivial...

Coleman's version of Mott's argument just uses a self-adjoint "straight line"/"linearity" operator L and the corresponding spectral...

Do you think that this argument is an original contribution by Coleman? Or is this argument artibutable to one of the given references...

Careful, he only said "associated with Hugh Everett". Since Coleman is very careful with words, this means that he is not claiming to...