Recent content by hoseA

An incandescent bulb has a resistance of 12 *omega when it is at room temperature (25 degrees C) and 400 omega * when it is hot and delivering light to the room. The temperature coefficient of re- sistivity of the filament is 0.008 (degrees C)^-1, where the base resistance R0 is determined...

http://img423.imageshack.us/img423/4778/hwhelp1bs.jpg The first one on the left is a Multiple Choice question. Just the mention of variables shuts down my brain. I'm still researching for the equation for the pbm. The pbm in the right upper corner i think it's C and E. (by simply...

help within the hour is much appreciated... I'm thinking maybe it should be negative?

Thanks for the confirmation.

Thanks. That helps. :approve:

o---o | o | o---o Four positive charges of magnitude q are ar- ranged at the corners of a square, as shown. At the center C of the square, the potential due to one charge alone is V0, and the electric field due to one charge alone has magnitude E0. Which of the following correctly...

Points A (3 m, 2 m) and B (6 m, 6 m) are in a region where the electric field is uniform and given by E = Exi + Eyj, where Ex = 3 N/C and Ey = 2 N/C. What is the potential difference VA-VB? Answer in units of V. I used E(rB-rA) sqr rt(13) times (sqr rt (72) - sqr rt (13)) = 17.59...

=( apparently that's incorrect. It's either V0>VA or "cannot be determined" I really need to get the answer right... since it's a multiple choice question -- -6.67 is my current score(negative)... if it's right i'll get -3.33 or -10 if it's wrong.

How do u arrive at this conclusion?

http://img69.imageshack.us/img69/6329/potential4iu.png i thought the electric potenial would be larger at Va than at V0. Va>V0 Apparently I'm wrong. I thought since R=0 at the origin the electric potential would also be zero. Is that not the case? Can the electric potential even...

any help within the next 10 min. much appreciated. I only have 1 try left. Is there supposed to be a "q" in the equation or is what quasar put correct? thanks.

Nevermind. i got it. Thanks for the help Gokul.

any more hints? i have to submit my homework in 20 min. :frown:

http://img90.imageshack.us/img90/358/electricforce8yv.png I know how to do the first question. The second question is what's troubling me. I don't know where the forces are supposed to be directed (i.e. to which charge)... basically i don't understand what I'm finding out. Any incite...

http://img209.imageshack.us/img209/2646/chargedrod1ew.png I used the equation: kq/(d(d+L)) I converted everything to meters before doing the calculations. (I'm kind of pressed for time at the moment... i'll post the actual work in 2 hours.) I want to make sure the equation is right.