Recent content by njama

Thanks a lot for the help, I have never heard about e-booksdirectory.com it's pretty cool site for free e-books. I've found courses from Stanford on Youtube about Convex Optimization and some applied linear algebra. Regards.

Hey! Happy New Year 2013 to all of you! I am in good mood for learning something new so I need advice. I'm currently watching the videos for Machine learning from Stanford University, but I'm stuck at Lagrangian multipliers and duality. I got solid background in Calculus I and II (I read...

Homework Statement Hello! I just want to be sure if I did solve the task correctly. The task is: Prove that bn is odd for integers n>=1 b1=1 b2=3 bk=bk-2+2bk-1 for k>=3 Homework Equations The Attempt at a Solution Induction basis: b1=1 true 1 is odd b2=3 true 2...

Sorry for misunderstanding but I meant starting edges (directed graph) or vertex with max indegree. Thank you.

any ideas please?

Homework Statement Prove the following: If the tournament graph is acyclic, there is exactly one vertex which got edges more than any vertex in the graph. Homework Equations A tournament is a directed graph (digraph) obtained by assigning a direction for each edge in an undirected...

You did it well. Regards.

f'(x) = g'(x) then by CDT (Constant Difference Theorem) f(x)=g(x)+C. Here is something to know: "The Constant Difference Theorem has a simple geometric interpretation - it tells us that if f and g have the same derivative on an interval, then there is a constant k such that f(x)=g(x)+k for...

You should grow mustache and beard, then you'll look like Johnny Deep. :smile:

Another idea: u=1-x du=dx x=1-u

Here is an efficient way: \frac{4x^5-1}{(x^5+x+1)^2} = \frac{Ax^4+B}{x^5+x+1}+\frac{Cx^4+D}{(x^5+x+1)^2} 4x^5-1 = (Ax^4+B)(x^5+x+1)+(Cx^4+D) I think it's much faster then the other methods.

You can do that, but you may need to consider both positive and negative square root of 5.10,

Yes, that's right. Thanks for the correction. I replaced \cup with \cap and vice versa.

Yes, that's true. Now try again, and use P(A_1\cup \left[ B_1\cap B_2 \cap B_3 \right] \cup A_2)

That's not correct. First, give me the correct information. When the current will break? I ask you this because you said that ALL of B need to fail, and then you write B1 U B2 U B3.