Recent content by rahiem01

Thank you. that makes a lot more sense to me now. i appreciate the help

so do I do Q_{water} + Q_{ice} = 0 m_{water}c_{water}(T_{2} -T_{1}) + m_{ice}L = 0

okay thanks for the info. i'll put it together and post a solution.

I think I am undertsanding the concept. I need to find the amount of energy to go from 10°C of water to -7°C of ice . Q_{ice} = mL_{c}, where m = mass and L_{c} = 3.34 X 10^{5}

okay, i understand what you're saying, but I'm not sure how to set up the equation to account for the latent heat.

okay, to make sure I'm on the right track. Q_{water} + Q_{ice} = 0, where Q = mc delta T. I then solve for T, plug back into Q_{water} then solve for m?

yeah, i know of that. I wasn't sure if I was over thinking it.

1. 30 kg of water at 10°C is mixed with 360 kg of ice at -7°C. (The heat capacity of water is 4190 J/(kg * °C), that of ice is 2090 J/ (kg *°C), and the heat of fusion of water is 3.34 * 10^{5} J/kg 1. What mass of water freezes? Homework Equations none that I know of. The Attempt...