Aha, so I should just apply it like that -
f(x) = e(x^x) -> f'(x) = e(x^x)
g(x) = x^x -> ln(g(x))=x*ln(x) -> g'(x)=x^x(ln(x)+1)
(f°g)'(x) = e(x^x)*x^x(ln(x)+1)
Thank you very much!
Homework Statement
Problem: e(x^x)
The Attempt at a Solution
I came up with - f'(x) = e(x^x)[ln(x)+1]. The solution should be - x^x*e(x^x)[ln(x)+1] . Can someone please help me understand why should I add x^x to the solution.
Much appreciated!